We have an Access 97 Database that was developed on a PC with a locally installed version of Office 97
One of the functions of this database includes a button on a form that conditionally opens any one of a number of other Access databases (mdbs) depending on user input. To do this it uses the Call Shell function... e.g.
if condition = x then
call shell ("c:\program files\microsoft office\office\msaccess.exe ""path.mdb""",1)
this process runs fine on pc's with locally installed MS Office 97, but fails on pc's that run thinapped versions of Office 97.
We figure its the path to the access executable that is causing the problem, because the pc's running thinapp obviously don't have a c:\program files\microsoft...... path
what should the syntax be to launch the thinapp access executable ?